
Given :-
- wide of the hall (Breadth) = 10m
To Find :-
- Surface area of the walls (Four walls area)
Formula :-
Four walls area of the hall = 2h(l+b)
where,
Solution : -
By substituting values according to the formula,
➙ 2 × 4m(12m + 10m)
➙ 8m(22m)
➠ 176m²
It's option B
Hence, The surface area of the walls is (B) 176m²