Question

If the length of a square is x + 4 1/2, what is the perimeter?

Answer 1

let's recall that a square has four equal sides, so if one side is x + 4½ long, then all four are x + 4½ long, and the perimeter is simply the sum of all four.

let's first off, convert the mixed fraction to improper fraction.

`\bf \stackrel{mixed}{4(1)/(2)}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \left( x+\cfrac{9}{2} \right)+\left( x+\cfrac{9}{2} \right)+\left( x+\cfrac{9}{2} \right)+\left( x+\cfrac{9}{2} \right)\implies 4\left( x+\cfrac{9}{2} \right) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 4x+18~\hfill`

Answer 2

Answer: Perimeter of square would be 4x+18 units.

Explanation:

Since we have given that

Length of square =
`x+4(1)/(2)`

So, after simplification, we get that

`x+(4* 2+1)/(2)\\\\=x+(9)/(2)`

As we know the formula for "Perimeter of square";

Perimeter of square is given by

`4* side\\\\=4* (x+(9)/(2))\\\\=4x+4* (9)/(2)\\\\=4x+(36)/(2)\\\\=4x+18`

Hence, Perimeter of square would be 4x+18 units.