Question

Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object

Answer 1

For 3 kg mass: F =
`\lpha ma,a` =
`(F)/(m)` =
`(12N)/(3kg)` = 4
`\lpha m` /
`s^(2)`

For 6 kg mass: F =
`\lpha ma,a` =
`(F)/(m)` =
`(12N)/(6kg)` = 2
`\lpha m` /
`s^(2)`

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