Question

If f(3)=191.5 when r =0.03 for the function F(t)=pe^rt, then what is the approximate value of P?

A. 175
B. 78
C. 210
D. 471

Answer 1

A. 175

Explanation:

Answer 2

The correct option is A.

Explanation:

The given function is

`F(t)=pe^(rt)`

It is given that f(3)=191.5 and r =0.03.

Substitute t=3 and r=0.03 in the given function.

`F(3)=pe^(0.03(3))`

`F(3)=pe^(0.09)`

The value of F(3)=191.5. Put F(3)=191.5 in the above equation.

`191.5=p(1.0942)`

Divide both sides by 1.0942.

`(191.5)/(1.0942)=p`

`175.0137=p`

`p\approx 175`

The approximate value of p is 175. Therefore the correct option is A.