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I need to solve for p and have a rationalized denominator

I need to solve for p and have a rationalized denominator-example-1
User Sihil
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1 Answer

3 votes

Answer:


p = \pm (√(r(st - 1)))/(st - 1)

or


p = (√(r(st - 1)))/(st - 1)

Explanation:


t = (p^2 + r)/(p^2s)


p^2st = p^2 + r


p^2st - p^2 = r


p^2(st - 1) = r


p^2 = (r)/(st - 1)


p = \pm \sqrt{(r)/(st - 1)}

Your picture cuts out the assumption. If the assumption is that all variables are non-negative, then the answer is


p = \sqrt{(r)/(st - 1)}


p = (√(r))/(√(st - 1))}


p = (√(r))/(√(st - 1))} * (√(st - 1))/(√(st - 1))


p = (√(r) √(st - 1))/(√(st - 1)√(st - 1))


p = (√(r(st - 1)))/(st - 1)

User Soul Clinic
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