Question

20 PTS! Help!
 How do you solve the following:

Answer 1

Answer:
`3x^2-x+2`

Step-by-step explanation:

The area of a triangle A can be calculated as A=(height)x(base)/2

We know the height is 6x.

We know
`A=9x^3-3x^2+6x`

So the equation becomes (using |AC| as the base length):

`9x^3-3x^2+6x = (6x \cdot |AC|)/(2)\\(9x^3-3x^2+6x)/(3x)=|AC|\\(3x^2-x+2)/(1)=|AC|\\|AC|=3x^2-x+2`

The base is
`3x^2-x+2`