Question

Please help me with my Pre-Cal!

A population of bacteria is growing according to the equation P(t)=800e^0.13t.
Use a graphing calculator to estimate when the population will exceed 1474.
T=?
Please help me! Thanks so much.

Answer 1

when is

1474 = 800e^0.13t.

/800 /800

1.8425 = e^0.13t.

ln 1.8425 = ln e^0.13t. (us natural lg LN on your calc)

ln 1.8425 = 0.13t ln e (ln e is 1)

ln 1.8425 = 0.13t

/0/13 /0.13

ln 1.8425/0.13 = t

answer is number of years

in your calc type

(ln(1.8425))/0.13