Question

Solve the equation x^2-12x+32=0.

A.x=-1/4 or x=-13
B.x=8 or x=4
C.x=2 or x=-6
D.x=-1/4 or x=13

Answer 1

`x^2-12x+32=0\\\\x^2-8x-4x+32=0\\\\x(x-8)-4(x-8)=0\\\\(x-8)(x-4)=0\iff x-8=0\ \vee\ x-4=0\\\\\boxed{x=8\ \vee\ x=4}\to\boxed{B.}`