1 nickel = 5 cents
1 quarter = 25 cents
Let the number of nickels be = n
Let the number of quarters be = q
As mentioned, Chris has 4 times as many nickels as quarters
so, n=4q ----- (1)
The coins have a combined value of 180 cents, so
----- (2)
Putting n=4q in equation (2)
![5(4q)+25q=180](https://img.qammunity.org/2019/formulas/mathematics/high-school/wm8d9tr1opever8vw3nup6wp4apwscmsz9.png)
![20q+25q=180](https://img.qammunity.org/2019/formulas/mathematics/high-school/hq1favd5d2ab943aat8tx4tw6vojdghf0p.png)
![45q=180](https://img.qammunity.org/2019/formulas/mathematics/high-school/hbzjwzmp1u1ie0gjpunsnov687kmbwgnqn.png)
![q=4](https://img.qammunity.org/2019/formulas/mathematics/high-school/5b6hsxfr1ej7gaw0ldw5nikbnket79gt2j.png)
Hence, quarters are 4
As, n=4q
![n=4*4=16](https://img.qammunity.org/2019/formulas/mathematics/high-school/cvapl89k2nsm10bjanzj5oo8hrvgyfzq8a.png)
Hence, nickels are 16