Question

A 0.145 kg baseball is travelling at 42 m/s. What velocity must a 3.2 kg bowling ball be moving with to have the same momentum?

Answer 1

8.94 m/s

Step-by-step explanation:

Kinetic Energy = 1/2 m v^2

baseball KE = BB KE

1/2 * .145 * 42^2 = 1/2 * 3.2 * v^2

.145 * 42^2 / ( 3.2) = v^2 v = 8.94 m/s for the bowling ball