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Find the exponential function that satisfies the given conditions:

Initial value = 67, decreasing at a rate of 0.47% per week

f(t) = 0.47 ⋅ 0.33t

f(t) = 67 ⋅ 1.47t

f(t) = 67 ⋅ 1.0047t

f(t) = 67 ⋅ 0.9953t

2 Answers

3 votes

Answer:

a = starting amount = 67

r = rate = 0.47% = 0.0047

t = week

User Henley N
by
9.3k points
2 votes

Answer-

The exponential function that satisfies the given conditions is
f(t)=67(0.9953)^t

Solution-

This can be represented as exponential decreasing function,


f(t)=a(1 - r)^t

Where,

  • a = starting amount = 67
  • r = rate = 0.47% = 0.0047
  • t = week

Putting the values,


\Rightarrow f(t)=67(1 - 0.0047)^t


\Rightarrow f(t)=67(0.9953)^t

Therefore, the exponential function that satisfies the given conditions is


f(t)=67(0.9953)^t

User Alex Kucksdorf
by
7.5k points