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The sum of three consecutive numbers is 72 what are the smallest of these numbers

1 Answer

2 votes
a + b + c = 72

a = b - 1

c = b + 1



(b - 1) + b + (b + 1) = 72

Simplify

3b = 72

b = 24



a = 24 - 1

a = 23


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