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Which two values of x are roots of the polynomial below?

x2 - 11x + 13

User Djinn
by
8.0k points

2 Answers

4 votes

Answer:

(11+sqrt69)/2

or

(11-sqrt69)/2

Explanation:

ap3x

User JahMyst
by
7.4k points
7 votes

Answer-

The values of x, which are the roots of the polynomial are


(11+ √(69))/(2),\ (11- √(69))/(2)

Solution-

The given polynomial,


=x^2 - 11x + 13

We know that,


x=(-b\pm √(b^2-4ac))/(2a)

Here,

a = 1, b = -11, c = 13

Putting the values,


x=(-(-11)\pm √((-11)^2-4* 1* 13))/(2* 1)


=(11\pm √(121-52))/(2)


=(11\pm √(69))/(2)


\therefore x=(11+ √(69))/(2),\ (11- √(69))/(2)

User Irzhy
by
7.2k points