Question

Arrange the distances between Earth and various celestial objects in order from least to greatest. Use the conversion table to help you. 1 AU 1.5 × 108 km 1 ly 63,000 AU 1 pc 3.262 ly distance to the star Betelgeuse: 640 ly distance to the star VY Canis Majoris: 3.09 × 108 AU distance to the galaxy Large Magellanic Cloud: 49976 pc distance to Neptune at the farthest: 4.7 billion km ↓ ↓ ↓

Answer 1

Distance to Neptune at the farthest >distance to the star Betelgeuse >distance to the star VY Canis Majoris > distance to the galaxy Large Magellanic Cloud

Step-by-step explanation:

Answer 2

Distance to Neptune at the farthest < distance to the star Betelgeuse < distance to the star VY Canis Majoris < distance to the galaxy Large Magellanic Cloud

Step-by-step explanation:

Firstly, we need to work with the same units in order to make the comparison among the given distances. So, let's work with kilometers (
`km`):

distance to the star Betelgeuse: 640 ly

`640 ly (63000 AU)/(1 ly) (1.5(10)^(8) km)/(1 AU)=6.048(10)^(15) km`

distance to the star VY Canis Majoris: 3.09 × 108 AU

`3.09(10)^(8) AU (1.5(10)^(8) km)/(1 AU)=4.635(10)^(16) km`

distance to the galaxy Large Magellanic Cloud: 49976 pc

`49976 pc (3.262 ly)/(1 pc) (63000 AU)/(1 ly) (1.5(10)^(8) km)/(1 AU)=1.54(10)^(18) km`

distance to Neptune at the farthest: 4.7 billion km

`4.7 billion km=4.7(10)^(12) km`

Now that we have all the distances in kilometers we can compare and arrange them in order from least to greatest:

Distance to Neptune at the farthest:
`4.7 billion km=4.7(10)^(12) km`

Distance to the star Betelgeuse:
`640 ly=6.048(10)^(15) km`

Distance to the star VY Canis Majoris:
`3.09(10)^(8) AU=4.635(10)^(16) km`

Distance to the galaxy Large Magellanic Cloud:
`49976 pc=1.54(10)^(18) km`