Question

write an equation of a line in slope intercept gorm with a slope of 5 and a y intercept of 8. Then graph it

Answer 1

`\bf \begin{array} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{7em}y=5x+8`

to graph a line, all you need is two points, so, we know the y-intercept is at 8, namely the graph touches or intercepts the y-axis at 8, so that's one point, (0,8).

let's get another point, a random "x", say x = -2, y = 5(-2)+8 => y = -2, so (-2, -2).

check the picture below.