Question

How much heat is absorbed by a 26g iron skillet when its temperature rises from 13oC to 26oC?

HELP ASAP

Answer 1

Answer:- 152.1 J

Solution:- This type of problems are solved by using the formula:

`q=mc\Delta T`

where, q is the heat energy, m is the mass, c is specific heat and
`\Delta T` is change in temperature.

mass of iron is given as 26 g. temperature is changing from 13 degree C to 26 degree C.

So,
`\Delta T` = 26 - 13 = 13 degree C

specific heat for iron is 0.450 Joule per gram per degree C.

let's plug in the values in the formula and do calculations for q.

`q=26g*(0.450J)/(g.^0C)*13^0C`

q = 152.1 J

So, 152.1 J of heat is absorbed by the iron skillet.