Answer:
Explanation:
There are 3 graphs
Graph B:
f(x) = 9, -5<x<5
Symmetrical about x =0
To the right of x = 5, Passes through (5,9) and (15,30)
Use two point formula
y-9/(30-9) = x-5/(15-5) or 21(x-5) = 10(y-9)
21(x-5) = 10(y-9)
because of symmetry about x =0, we get
equation as
f(x) = 2.1(x-5|)+90, for |x|>5
=9, for |x|<5
Graph C is symmetric about x =-5
Hence the equation has an |x+5| in it
Because both sides straight line, right line passes through (-5,0) and (0,5) and hence right equation is x/-5 +y/5 =1
Or x-y = -5
Or y =x+5
Left side line is y = -x-5
Put together y = f(x) = |x+5| for graph C
iii) GraphD:
Graph D has 3 different lines. Between 4 and t f(x) = 1
For x<4, Line passes through (3,3) and (4,1)
Using two point formula, y-3/(1-3) = x-3/(4-3)
Or -2x+6 = y-3 or 2x+y =9, for x <=4
For x>=4, line passes through (5,1) and (6,3)
Equation is (y-1)/(3-1) = (x-5)/(6-5) Or 2x-10 =y-1
2x-y =9
Together we can write f(x) as
y = |2x+9|,for x<=4 and x>=5
= 1, for 4<x<5