Question

What are the excluded values for 1/x-x/9=0. Please explain how you get you answer

Answer 1

Excluded values are the values that make the denominator 0

Denominator 0 is undefined so we exclude the values that makes the denominator 0

`(1)/(x) - (x)/(9) =0`

LCD is 9x

Multiply the first fraction by 9 and second fraction by x

`(1*9)/(x*9) - (x*x)/(9*x) =0`

`(9-x^2)/(9x) =0`

We have 9x in the denominator

When x=0 the denominator becomes 0

so excluded value is x=0