Question

How many atoms of oxygen are in 566 g of glucose? * How many molecules are there in 43 grams of sodium hydroxide? * How many atoms of fluorine are in 5.5 x 10^24 molecules of sulfur hexafluoride? *

Answer 1

See explanation

Step-by-step explanation:

Number of moles of glucose in 566g = 566g/180g/mol = 3.14 moles

Number of moles of oxygen atoms in 1 mole of glucose= 6 * 16g/16g/mol = 6 moles.

There are 6 moles of oxygen in 1 mole of glucose

x moles of oxygen is therefore present in 3.14 moles of glucose

x = 6 * 3.14/ 1 = 18.84 moles of oxygen

1 mole of oxygen contains 6.02 * 10^23 atoms of oxygen

18.84 moles of oxygen contains 18.84 * 6.02 * 10^23 atoms = 1.14 * 10^25 atoms of oxygen.

Number of moles of sodium hydroxide in 43g of NaOH = 43g/40g/mol = 1.075 moles

1 mole of NaOH contains 6.02 * 10^23 molecules of NaOH

1.075 moles of NaOH contains 1.075 moles * 6.02 * 10^23 molecules / 1 mole of NaOH = 6.47 * 10^23 molecules of NaOH

Number of moles of atoms fluorine in SF6 = 6 * 19 g/19 g/mol = 6 mole of F atoms

1 mole of SF6 contains 6.02 * 10^23 molecules of SF6

x moles of SF6 contains 5.5 x 10^24 molecules of SF6

X = 5.5 x 10^24 molecules * 1/ 6.02 * 10^23 molecules

X = 9 moles of SF6

If 1 mole of SF6 contains 6 atoms of F

9 moles of SF6 will contain 9 * 6/1 = 54 atoms of F