Question

What is the equation of the line ?

Answer 1

Look at the picture.

The point-slope form:

`y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)`

We have the points (-3, -3) and (2, 0). Substitute:

`m=(0-(-3))/(2-(-3))=(3)/(5)\\\\y-0=(3)/(5)(x-2)\qquad|\text{use distributive property}\\\\y=(3)/(5)x-(6)/(5)\qquad|\cdot5\\\\5y=3x-6\qquad|-5y\\\\0=3x-5y-6\qquad|+6\\\\3x-5y=6`

Answer:

point-slope form:
`y=(3)/(5)(x-2)`

slope-intercept form:
`y=(3)/(5)x-(6)/(5)`

standard form:
`3x-5y=6`