Question

NEED HELP RN PLZ!!!!!!!!!!!!!!!!!!!!!Complete the square to find the zeros of y=x^2+12x-5?

Answer 1

Answer: -6 +/-
`√(41)` = x

Explanation:

y = x² + 12x - 5

+5 +5

y + 5 = x² + 12x

+ 36 +36 added (12 ÷ 2)² to both sides

y + 41 = (x + 6)²

To find the zeros, let y = 0:

0 + 41 = (x + 6)²

`√(41) = (√(x+6) )^(2)`

`+/-√(41)` = x + 6

-6 -6

-6 +/-
`√(41)` = x