Answer:
1) 79
2) 400
3) 29
Explanation:
1) To find : Tell which number is prime: 18, 42, 68, 79.
Solution :
A prime number is defined as number which is only divisible by 1 and itself.
As 18,42 and 68 were divisible by 2.
But 79 is not divisible by any number.
Which means 79 is the only prime number which is divisible by 1 and itself.
2) To find : The value of the expression
![48* 8+4* 4](https://img.qammunity.org/2019/formulas/mathematics/high-school/km05pfvqxn9m3l438xejnh2c294ylz9tdy.png)
Solution :
The expression,
![48* 8+4* 4](https://img.qammunity.org/2019/formulas/mathematics/high-school/km05pfvqxn9m3l438xejnh2c294ylz9tdy.png)
![=384+16](https://img.qammunity.org/2019/formulas/mathematics/high-school/6dpze3tz73zfr2srstj88f6d0q5islpzq0.png)
![=400](https://img.qammunity.org/2019/formulas/mathematics/high-school/98o7v5dljddg5t0gl7umn64e4mc7ebqt0i.png)
Therefore,
![48* 8+4* 4=400](https://img.qammunity.org/2019/formulas/mathematics/high-school/5jf0mglbzbjzubsbg68b6kch48w0qd3tbz.png)
3) Evaluate :
for a=-5, b=-2 and c=-4
Solution :
The expression is
![(c- b)^2 + a^2](https://img.qammunity.org/2019/formulas/mathematics/high-school/ovw12e931vbu4t6w1ieh00yt2cazr7dxfa.png)
Substitute the values, a=-5, b=-2 and c=-4
![(c- b)^2 + a^2=(-4-(-2))^2+(-5)^2](https://img.qammunity.org/2019/formulas/mathematics/high-school/ps31rzyg4oo7duq96szqxzwbk1idg6s9hk.png)
![(c- b)^2 + a^2=(-4+2)^2+25](https://img.qammunity.org/2019/formulas/mathematics/high-school/w7jdj6u992ao3zi63hqjs13ch97pb7shv4.png)
![(c- b)^2 + a^2=(-2)^2+25](https://img.qammunity.org/2019/formulas/mathematics/high-school/bprwwjbsay3car7raaxmce80c8qw8wjbki.png)
![(c- b)^2 + a^2=4+25](https://img.qammunity.org/2019/formulas/mathematics/high-school/9vdkivgozzhzauspk1mydfmgrforsdtri4.png)
![(c- b)^2 + a^2=29](https://img.qammunity.org/2019/formulas/mathematics/high-school/6d60jvjrgylzjmyt2wf703k2fqnrlq1e40.png)