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0=-16t^2 +10 Solve for t

User Ryan J
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2 Answers

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0=-16t^2 +10 \\\\16t^2=10\\\\t^2=(10)/(16)=(5)/(8)\\\\t=\sqrt{(5)/(8)} \vee t=-\sqrt{(5)/(8)}\\\\t=(\sqrt5)/(\sqrt8) \vee t=-(\sqrt5)/(\sqrt8)\\\\t=(\sqrt5)/(2\sqrt2) \vee t=-(\sqrt5)/(2\sqrt2)\\\\t=(√(10))/(2\cdot2) \vee t=-(√(10))/(2\cdot2)\\\\t=(√(10))/(4) \vee t=-(√(10))/(4)

User Osama F Elias
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6 votes

Answer:

plus or minus √10 / 4

Explanation:

0=-16t^2 +10 becomes easier to solve if we rewrite it as 16t^2 = 10.

Then t^2 = 10/16 = 5/8, and t = plus or minus √(5/8), or

t = plus or minus (√5) / √8), or

t = plus or minus (√5)√8 √5*2√2

------------- = -------------------

8 8

or plus or minus √10 / 4

User Brian Tung
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