Question

A tennis ball of mass 0.060 kg travels horizontally at a speed of 25m/s. The ball hits a tennis

racket and rebounds horizontally at a speed of 40 m/s.

Before hitting the Racket, the ball is going towards the racket at 25 m/s.

After Hitting the Racket the ball of going away from the racket at 40 m/s.

The ball is in contact with the racket for 50 ms.
What force does the racket exert on the ball?
A 0.018N
B 0.078N
C 18N
D 78N

Answer 1

The force exerted by the racket on the ball can be calculated using Newton's second law of motion. By calculating the acceleration and applying it to the mass of the ball, we find that the force is 18 N.

Step-by-step explanation:

To calculate the force exerted by the racket on the ball, we can use Newton's second law of motion which states that force equals mass times acceleration (F = ma). We can find the acceleration by using the change in velocity and the time of contact.

Given:

• Mass of the ball (m) = 0.060 kg
• Initial velocity of the ball (u) = 25 m/s
• Final velocity of the ball (v) = 40 m/s
• Time of contact (t) = 0.050 s

Acceleration (a) can be calculated using the formula:

a = (v - u) / t

a = (40 - 25) / 0.050

a = 300 m/s^2

Now, we can calculate the force (F) using the formula:

F = ma

F = 0.060 kg * 300 m/s^2

F = 18 N

Therefore, the force exerted by the racket on the ball is 18 N. So, the correct answer is option C) 18N.