Complete question is;
Two separate bacteria populations grow each month and are represented by the functions f(x) = 3^(x) and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population?
A. Month 1
B. Month 2
C. Month 3.
D. Month 4
Answer:
Option D: Month 4
Explanation:
We are given the functions;
f(x) = 3^(x)
And g(x) = 7x + 6
We want to find the month when f(x) > g(x)
Thus;
3^(x) > 7x + 6
For option A, month 1 means x = 1.thus;
LHS is 3¹ = 3
RHS = 7(1) + 6 = 13
Our LHS is not greater than RHS as the question demands, thus this option is not correct
For option B, month 2 means x = 2. thus;
LHS is 3² = 9
RHS = 7(2) + 6 = 20
Our LHS is not greater than RHS as the question demands, thus this option is not correct
For option C, month 3 means x = 3. thus;
LHS is 3³ = 27
RHS = 7(3) + 6 = 27
Our LHS IS equal to the RHS and not greater than RHS as the question demands, thus this option is not correct
For option D, month 4 means x = 4. thus;
LHS is 3⁴ = 81
RHS = 7(4) + 6 = 34
Our LHS is greater than RHS as the question demands, thus this option is correct