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In triangle QRS, if QR is congruent to RS, angle Q = 8x - 17, angle R = 19x + 4, & angle S = 5x + 1, find x & the measure of each angle.

User Reuscam
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2 Answers

1 vote

Answer:

x=6


\angle Q=\angle S=31^(\circ)


\angle R=118^(\circ)

Step-by-step explanation:

We are given that in triangle QRS


\angle Q=8x-17


\angle R=19x+4


\angle S=5x+1


QR\cong RS

We have to find the value of x and the measure of each angle

We know that congruent sides make congruent angles

Therefore,
\angle Q=\angle S


8x-17=5x+1


8x-5x=1+17


3x=18


x=(18)/(3)=6

Substitute the value of x


\angle Q=8(6)-17=31^(\circ)


\angle R=19(6)+4=118^(\circ)


\angle S=5(6)+1=31^(\circ)

User Haansi
by
5.5k points
2 votes

Answer:

Angle Q = 31°

Angle R = 118°

Angle S = 31°

Step-by-step explanation:

If QR is congruent to RS, from figure given we have angle Q = angle S.

Angle Q = 8x -17

Angle R = 19x + 4

Angle S = 5x + 1

We have,

8x -17 = 5x + 1

3x = 18

x = 6

So,

Angle Q = 8*6 -17 = 31°

Angle R = 19*6 + 4 = 118°

Angle S = 5*6 + 1 = 31°

In triangle QRS, if QR is congruent to RS, angle Q = 8x - 17, angle R = 19x + 4, &amp-example-1
User Vitalii Isaenko
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4.7k points