Question

What is the distance between (-2 1/3,-3) and (1,-3)? (In fraction form)

Answer 1

`\text{The formula of a distance between two points}\\\\d=√((x_2-x_1)^2+(y_2-y_1)^2)\\\\\text{We have the points}\ \left(-2(1)/(3);\ -3\right)\ \text{and}\ (1,\ -3).\\\\\text{Substitute}\\\\d=\sqrt{\left(1-\left(-2(1)/(3)\right)\right)^2+(-3-(-3))^2}=\sqrt{\left(3(1)/(3)\right)^2+(-3+3)^2}\\\\=\sqrt{\left(3(10)/(3)\right)^2+0^2}=\sqrt{\left(3(1)/(3)\right)^2}=3(1)/(3)\\\\Used\ √(a^2)=a`