For this case we have the following equation:
![y + 6 = -3y + 26](https://img.qammunity.org/2019/formulas/mathematics/college/yyul8wzxxsjmwtjt39u263o68rr8bng7od.png)
To clear the value of and we have the following steps:
1st step:
We subtract 6 on both sides of the equation:
![y + 6-6 = -3y + 26-6\\y = -3y + 20](https://img.qammunity.org/2019/formulas/mathematics/college/kiu24dwtgan22y7zmik6nebkz9vahehcc1.png)
2nd step:
We subtract "y" from both sides of the equation:
![y-y = -3y-y + 20\\0 = -4y + 20](https://img.qammunity.org/2019/formulas/mathematics/college/xp1z89hyu8y0298o2sdzt0k49jx1mi8z6v.png)
3rd step:
We add
to both sides of the equation:
![0 + 4y = -4y + 4y + 20\\4y = 20](https://img.qammunity.org/2019/formulas/mathematics/college/4wa0dunfxp5kag6l4pnp6hak9oq7tllkne.png)
4th step:
We divide between 4 sides of the equation:
![(4y)/(4)=(20)/(4)\\y = 5](https://img.qammunity.org/2019/formulas/mathematics/college/yynp5pw8jbvb2eij5856udx96m520tapfp.png)
Thus, the value of y is 5.
Answer:
![y = 5](https://img.qammunity.org/2019/formulas/mathematics/high-school/ofxlgjgwq5gpsrtxb38qhr9oxrwmtvbm37.png)
Option C