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Differentiate the function

7 {x}^(3) + x / 6 √(x)

1 Answer

4 votes

There are two likely interpretations for the given function:


f(x)=7x^3+\frac x{6\sqrt x}

in which case you can write


\frac x{6\sqrt x}=\frac x{6x^(1/2)}=\frac16x^(1/2)

and the derivative is


f'(x)=21x^2+\frac1{12}x^(-1/2)=21x^2+\frac1{12\sqrt x}

Or, perhaps it is


f(x)=(7x^3+x)/(6\sqrt x)=\frac76x^(5/2)+\frac16x^(1/2)


\implies f'(x)=(35)/(12)x^(3/2)+\frac1{12\sqrt x}

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