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29 votes
29 votes
Slope intercept form (-6,19) and (3,-2)

User PiotrNycz
by
2.5k points

2 Answers

18 votes
18 votes

Answer:


y = -(7)/(3)x +5

Explanation:

The general equation of a line in slope-intercept form is

y = mx + b

where m = slope and b = y-intercept is rise over run


m = \frac {(y_(2) - y_(1))} {(x_(2) - x_(1))}

where (x₁, y₁) and (x₂, y₂) are any two points on the line

For the line passing through (-6, 19) and (3, -2) , the slope


m = (-2 - 19)/(3 - (-6))\\\\


\\\\m= (-21)/(9)


m = -(7)/(3)

So slope-intercept form is

y = -(7)/(3)x +b\\\\

To compute y-intercept, b, plug in any of the two points into the above equation and solve for b

Let's choose point (3, -2)

Plugging x = 3 and y = -2 gives


-2 = -(7)/(3)\cdot 3 +b\\\\\\\\-2 = -7 + b\\\\

So equation of line is

y = -(7)/(3)x +5

User Mary Chang
by
2.9k points
11 votes
11 votes

Answer:

-7/3 or -2.3

Explanation:

1. y2-y1 divided by x2-x1 which would be y2-y1/x2-x1

2. plug in : -2-19/3-(-6)

4. Solution ( -7.3 or -2.3 )

User Azer
by
2.4k points
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