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What is the equation of a line, in general form, that passes through points (-1, 2) and (5, 2)? y - 2 = 0 x - 2 = 0 y - x - 2 = 0

User Charleshaa
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2 Answers

4 votes

The point-slope form:


y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)

We have the points (-1, 2) and (5, 2). Substitute:


m=(2-2)/(5-(-1))=(0)/(6)=0\\\\y-2=0(x-(-1))\\\\y-2=0

Answer: y - 2 = 0.

User Joshu
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8.9k points
1 vote

Answer:


y- 2=0

Explanation:

Given : A line passes through points (-1, 2) and (5, 2).

To find : What is the equation of a line.

Solution : We have given points (-1, 2) and (5, 2).

General form of line equation :


y-y_(1) =((y_(2)-y_(1))/(x_(2)-x_(1)))(x-x_(1)).

Here,
y_(1) = 2.\\y_(2) =2\\x_(1) =-1\\x_(2) =5.

Plug the values


y- 2 =((2-2)/(5+1))(x+ 1).


y- 2=0.

Therefore,
y- 2=0.

User Mritunjay Upadhyay
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7.6k points

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