Question

What is the equation of a line, in general form, that passes through points (-1, 2) and (5, 2)? y - 2 = 0 x - 2 = 0 y - x - 2 = 0

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)\\\\m=(y_2-y_1)/(x_2-x_1)`

We have the points (-1, 2) and (5, 2). Substitute:

`m=(2-2)/(5-(-1))=(0)/(6)=0\\\\y-2=0(x-(-1))\\\\y-2=0`

Answer: y - 2 = 0.

Answer 2

`y- 2=0`

Explanation:

Given : A line passes through points (-1, 2) and (5, 2).

To find : What is the equation of a line.

Solution : We have given points (-1, 2) and (5, 2).

General form of line equation :

`y-y_(1) =((y_(2)-y_(1))/(x_(2)-x_(1)))(x-x_(1))`.

Here,
`y_(1) = 2.\\y_(2) =2\\x_(1) =-1\\x_(2) =5`.

Plug the values

`y- 2 =((2-2)/(5+1))(x+ 1)`.

`y- 2=0`.

Therefore,
`y- 2=0`.