Question

What is the point-slope form of the line with slope

− 1/8
that passes through the point (−2, 1)? Multiple
choice

Answer 1

For this case we have that the point-slope form of a line is given by:

`(y-y_ {1}) = m (x-x_ {1})`

Where:

m: is the slope

`(x_ {1}, y_ {1})` are the coordinates of a point through which the line passes.

In this case we have to:

`m = - \frac {1} {8}\\(x_ {1}, y_ {1}) = (-2, 1)`

Substituting we have:

`(y-1) = - \frac {1} {8} (x - (- 2))`

Simplifying:
`- * - = +`

`(y-1) = - \frac {1} {8} (x + 2)`

Thus, the point-slope equation form of the line is:
`(y-1) = - \frac {1} {8} (x + 2)`

Answer:

`(y-1) = - \frac {1} {8} (x + 2)`