71.7k views
4 votes
A diner asks patrons for their preference for waffles or pancakes and syrup or fruit topping.

The table shows the probabilities of results.

A diner asks patrons for their preference for waffles or pancakes and syrup or fruit-example-1
User Kiwixz
by
6.3k points

2 Answers

3 votes

Answer:


P (Waffles | Syrup)\\eq P(Waffles)

Explanation:

From the table we have to:

Probability of syrup is 0.96

Probability of waffles and syrup is 0.32

P (Waffles | Syrup) = P (Waffles and syrup) / P (syrup)

So:

If this equality is met, the probabilities are dependent, if on the contrary

P (Wafles | Syrup) = P (Wafles) then are independent probabilities.


P (Wafles | Syrup) = 0.32 / 0.96 = 0.333 \\eq 0.32

So we have to:


P (Waffles | Syrup)\\eq P(Waffles)

The probabilities are dependent.

User Sekou
by
6.0k points
1 vote

Answer:

Preference for waffies and syrup are dependent events and


P(waffies\mid syrup)\\eq P(waffies)

Explanation:

Since we have given that


P(waffies)=0.34


P(syrup\cap waffies)=0.32

As we know that if A and B are independent it must satisfy ,


PA\cap B)=P(A).P(B)

But here,


P(waffies\cap syrup)\\eq P(waffies).P(syrup)\\0.32\\eq 0.34* 0.96\\0.32\\eq 0.3264

Hence, they are not independent i.e. they are dependent.

And


P(waffies\mid syrup)\\eq P(waffies)

Because,


P(waffies\mid syrup)\\\\=(P(waffies\cap syrup))/(P(syrup))\\\\=(0.32)/(0.96)\\\\=0.33

but,


P(waffies)=0.34


User Rspacer
by
6.6k points