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If 15.7 grams of A1203 are produced, how many grams of iron (Fe) were produced? 2 Al(s) + 3 FeO(s) → 3 Fe(s) + Al2O3(
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If 15.7 grams of A1203 are produced, how many grams of iron (Fe) were

produced?
2 Al(s) + 3 FeO(s) → 3 Fe(s) + Al2O3(

User Michael Bisbjerg
by
2.7k points

1 Answer

14 votes
Answer:

77.4 g Fe

Step-by-step explanation:

g Al2O3 —— mol Al2O3 —— mol Fe —- g Fe

15.7 g Al2O3 x (1 mol Al2O3/101.959 g Al2O3) x (3 mol Fe/1 mol Al2O3) x (167.535 g Fe/1 mol Fe) = 77.4 g Fe
User Tarmo R
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