Question

Divide. (20x^2-12x+8)/(2x+8)

Answer 1

your answer is might be wrong 460

Answer 2

`10x-46+(188)/(x+4)`

Explanation:

The given problem is :

`(20x^(2)-12x+8)/(2x+8)`

Taking out and cancelling 2 common from both numerator and denominator.

We get
`(10x^(2)-6x+4)/(x+4)`

Divide the leading coefficient of numerator and divisor;

`(10x^(2) )/(x) =10x`

Quotient = 10x

Now, multiply x+4 by 10x =
`10x^(2) +40x`

Subtracting
`10x^(2) +40x` from numerator above in question.

Remainder =
`-46x+4`

Therefore,
`(10x^(2)-6x+4)/(x+4)` becomes:

`10x+(-46x+4)/(x+4)`

Again dividing the leading coefficient -46x by x; we get -46

Quotient = -46

Multiplying x+4 by -46, we get
`-46x-184`

Subtracting
`-46x-184` from
`-46x+4` we get 188

So, remainder = 188

Therefore, the equation in final form becomes:

`10x-46+(188)/(x+4)`