Question

PLEASE HELP IM ON THE VERGE OF TEARS AND I️ JUST WANT TO BE DONE WITH THIS! A pharmacist wishes to mix a solution that is 8% Minoxidil. She has on hand 100 ml of a 7% solution and wished to add some 10% solution to obtain the desired 8% solution. How much 10% solution should she add?

Answer 1

50mL of 8% solution

Explanation:

Givens

Let the number of mL of 10% solution needed = x

Let the number of mL of 7% solution to be used = 100

She needs an 8% solution.

10%*x + 100*7% = (100 + x)*8%

(10/100)*x + 100*7/100 = 100*8/100 + x*8/100 Multiply through by 100

10x + 700 = 800 + 8x Subtract 700 from both sides

10x + 700 - 700 = 800 - 700 + 8x

10x = 100 + 8x Subtract 8x from both sides.

10x - 8x = 100 Combine like terms on the left

2x = 100 Divide by 2

x = 100/2 Do the division

x = 50

You need to add 50 Ml of the 10% solution.

Check

Left Hand Side

100 mL of 7% = 7 mL of active ingredient.

50 mL of 10% = 5 mL of active ingredient

Total 12 mL of active ingredient

Right Hand Side

150 mL of 8% = 12 mL of active ingredient

And it checks.

Answer 2

100 (.07) + x (.10) = (100+x) (.08)

Amount * percent + amount* percent = (total amount) * desired percent

distribute

7 + .1 x = 8+.08x

subtract .08x from each side

7 +.02x = 8

subtract 7 from each side

.02x =1

divide by .02

x = 1/.02

x = 50

add 50 ml of the 10% solution