Question

In a series RL circuit, ET = 120 V, R = 40 Ω, and XL = 30 Ω. How much is EL?

Answer 1

Firstly, we will draw

RL series circuit

ET = 120 V, R = 40 Ω, and XL = 30 Ω

Firstly, we will find current

`I=(E_T)/(R+jX_L)`

now, we can plug values

and we get

`I=(120)/(40+j30)`

now, we can find voltage across L

`E_L=IjX_L`

so, we get

`E_L=(120)/(40+j30)(j30)`

now, we can find absolute value

`|E_L|=120(30)/(√(40^2+30^2)  )`

`|E_L|=120(30)/( 50 )`

`|E_L|=120(3)/( 5 )`

`|E_L|=72V`...............Answer