Question

Question help please these are them 3

Answer 1

Answer: 0

Explanation:

`log_(m) 1 = x`

1 = mˣ

1 = m⁰

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Answer:
`x = -(2)/(33)`

Explanation:

log₁₀ (1 - 6x) = 2 restriction: 1 - 6x > 0 ⇒ x <
`(1)/(6)`

1 - 6x = 10²

1 - 6x = 100

-1 -1

-6x = 99

`(-6x)/(-6) = (99)/(-6)`

x =
`-(2)/(33)`

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Answer:
`x = -(3)/(5)`

Explanation:

`\frac{1}{\sqrt[5]{27} }` = 3ˣ

`\frac{1}{\sqrt[5]{3^(3)} }` = 3ˣ

`\frac{1}{3^{(3)/(5) } }` = 3ˣ

`3^{-(3)/(5)` = 3ˣ

`-(3)/(5) = x`

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Answer:
`x = (5)/(9)`

Explanation:

ln 2 + ln x = ln 5 + ln (4x - 2)

ln (2(x)) = ln (5(4x - 2))

2x = 5(4x - 2)

2x = 20x - 10

-20x -20x

-18x = -10

`(-18x)/(-18) = (-10)/(-18)`

`x = (5)/(9)`