157k views
5 votes
each course at college x is worth either 3 or 4 credits the members of the swim team are taking a total of 49 courses that are worth a total of 161 credits

User Ravindu
by
5.8k points

2 Answers

5 votes

To answer this problem, you should set up a system of inequalities to model the total number of courses and credits. This would look like:

x+y=49

3x+4y=161

where x is the 3 credit courses and y is the 4 credit courses.


There are many ways to solve system of equation, but this would best be solved by the substitution method. On the first equation, subtract x from both sides to get y=49-x. Now, since we know what y equals, when can substitute "49-x" for y in the second equation and solve for x.

3x+4(49-x)=161

*Use the distributive property*

3x+196-4x=161

*Combine like terms*

-x+196=161

*Subtract 196 from both sides*

-x=-35

*Divide both sides by -1*

x=35


Now, that we know that the swim team took 35 3 credit courses, we can solve for y using the first equation.

*Plug in 35 for x*

35+y=49

*Subtract 35 from both sides*

y=14


The swim team took 35 3 credit courses and 14 4 credit courses.


Hope this helps!


User Martijn Visser
by
7.2k points
7 votes

x= number of credit courses

y = number of 4 credit courses

x+y = 49

solve for x

x=49-y

3x+4y=161

substitute x=49-y into above equation

3(49-y) +4y=161

distribute

147 -3y +4y=161

combine like terms

147+y=161

subtract 147 from each side

y=14

x=49-y

x=49-14

x=35

they took 35 3 credit courses and 14 4 credit courses

35*3+14*4 = 161 so it checks

subtract 147 from each side


User Abhinav Goyal
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.