Question

Factorise:
3x3-3x2y+xy2-x2y

Answer 1

`3x^3-3x^2y+xy^2-x^2y`

All terms have an x in them, so you factor that out first to get

`x(3x^2 -4xy+y^2)`

Now the 2nd degree equation will be of the form (3x- ... y)(x- ... y) and by just trying you find that the ... is just 1. So the factorization is:

`x(3x - y)(x - y)`