Answer:
The atomic weight (or atomic mass) of Vanadium is 50.9415 which means that a "mole" of Vanadium atoms (6.02 x 10^23 atoms) will have a mass of 50.9415 grams. So, 214.1 grams of Vanadium would have
(214.1 / 50.9415) * (6.02 x 10^23) = 2.530 x 10^24 atoms
Explanation: