As per Doppler's effect of sound we know that when source and observer moves with some relative velocity with respect to each other then the frequency of sound that observer will hear is different from the actual frequency of sound and it is known as Doppler's effect.
So here when relative motion of bike is towards the observer the frequency is given by

so the frequency heard by the observer will be more than actual frequency in this case
So now when relative motion of bike is away from the observer the frequency is given by

from above equation we can say that in this case frequency heard by observer will be less than actual frequency