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What is the equation,in point slope form,for a line that goes through (8,-4) and has a slope of -5/6

1 Answer

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The point-slope formula:


y-y_1=m(x-x_1)

We have


(8,\ -4)\to x_1=8,\ y_1=-4\\\\m=-(5)/(6)[/tx]</p><p>Substitute:</p><p>[tex]y-(-4)=-(5)/(6)(x-8)\\\\y+4=-(5)/(6)(x-8)

User Gcali
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