Question

Construct the triangle ABC using as coordinates of its vertices points A(−3, 0), B(4, 5), C(0, −4). Find the coordinates of intersection of side AB with the y-axis.

DO NOT GIVE ME THE ANSWER OF (0,2) IT IS WRONG!
Pls graph it and give me another answer 15 points!!!!!!!!!

Answer 1

Plot all points on the coordinate plane and combine these points by lines to get triangle ABC (see attached picture for details).

Write the equation of side AB:

`(x-(-3))/(4-(-3))=(y-0)/(5-0) ,\\ \\(x+3)/(7)=(y)/(5),\\ \\y=(5)/(7)x+(15)/(7).`

To find y-intercept you have to substitute x=0, then:

`y=(5)/(7)\cdot 0+(15)/(7)=(15)/(7)=2(1)/(7).`

The point
`\left(0,2(1)/(7) \right)` is the point where line AB intersects y-axis.