Question

Which conversions from scientific notation to standard notation are true? Check all that apply.

Answer 1

2,5,7, and 8 or b,e,g,h are correct

Explanation:

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Answer 2

For this case we have the following expressions:

a)
`1.71 * 10 ^ 3`, in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 3 times. So, we have:

`1.71 * 10 ^ 3 = 1,710`

b)
`8.05 * 10 ^ 5`, in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 5 times. So, we have:

`8.05 * 10 ^ 5 = 805,000`

c)
`2.4 * 10 ^ 4`, in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 4 times. So, we have:

`2.4 * 10 ^ 4 = 24,000`

d)
`8.25 * 10^(-3)`, in this case we have a negative exponent, therefore we move the decimal point as many times to the left as indicated by the exponent, that is, 3 times. So, we have:

`8.25 * 10^(-3) =0.00825`

e)
`7.09 * 10^(-6)`, in this case we have a negative exponent, therefore we move the decimal point as many times to the left as indicated by the exponent, that is, 6 times. So, we have:

`7.09 * 10^(-6) = 0.00000709`

f)
`3.99 * 10 ^ 5`, in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 5 times. So, we have:

`3.99 * 10 ^ 5 = 399,000`

g)
`8 * 10 ^ 7`, in this case we have a positive exponent, therefore we move the decimal point as many times to the right as indicated by the exponent, that is, 7 times. So, we have:

`8 * 10 ^ 7 = 80,000,000`

h)
`1.03 * 10^(-4)`, in this case we have a negative exponent, therefore we move the decimal point as many times to the left as indicated by the exponent, that is, 4 times. So, we have:

`1.03 * 10^(-4)= 0.000103`

Answer:

The correct options are: b, e, g and h