Question

A projectile is launched at 68.0° above the horizontal and at a speed of 55 m/s. How long will it take the projectile to reach maximum height?

Answer 1

5.2s

Step-by-step explanation:

We care about the vertical component of the velocity, which, in our case, is
`v_y=55 sin 68\° m/s \approx 51 m/s`. The projectile is affected by gravity, which means its velocity will decrease by
`g= 9.81 m/s` each second. Remembering that at maximum height velocity is zero, we can write
`0=51-9.81 t \rightarrow t= (51)/(9.81)\approx 5.2s`