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PLEASE HELP

What is the frequency of a photon whose energy (E) is 7.48 x 10 -6 J?​

User Timgeb
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1 Answer

17 votes
17 votes

Answer:

1.128*10¹⁹ [GHz].

Step-by-step explanation:

1) the initial formula is

E=hν, where ν - required frequency,

2) according to the formula above


\\u=(E)/(h);\\ \\u=(748*10^(-8))/(663*10^(-36))=1.128*10^(28)[Hz]

User Fadd
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