Question

trinda score 72,67,82, and 79 on her algebra tests . use an inequality to find the minimum score she can make on the final exam to pass the course with an average of 80 or higher

Answer 1

To find the minimum score Trinda can make on the final exam to pass the course with an average of 80 or higher, we set up an inequality and solve for the minimum score.

Step-by-step explanation:

To find the minimum score Trinda can make on the final exam to pass the course with an average of 80 or higher, we can set up an inequality. Let's represent the minimum score as x. The average of Trinda's algebra tests scores is given by: (72 + 67 + 82 + 79 + x) / 5. To pass the course with an average of 80 or higher, the inequality would be: (72 + 67 + 82 + 79 + x) / 5 ≥ 80.

To solve this inequality, we need to multiply both sides by 5 to eliminate the denominator: 72 + 67 + 82 + 79 + x ≥ 80 * 5. Simplifying this, we get: 300 + x ≥ 400. To isolate x, we subtract 300 from both sides: x ≥ 100.

Therefore, Trinda needs to score a minimum of 100 on her final exam to pass the course with an average of 80 or higher.

Answer 2

(72+67+82+79+f)/5 >=80 to find the average we add up all the scores and divide by the number. she took 4 tests plus the final which is 5. It must be greater than or equal to 80

(300+f)/5>=80 added up the test scores

300+f >= 400 multiply each side by 5

f>= 100 subtract 100 from each side

Trinda needs 100 or greater