Question

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car B traveled 22 mph faster than Car A. How fast did Car A travel? (The formula R⋅T=D , where R is the rate of speed, T is the time, and D is the distance can be used.) Enter your answer in the box.

Answer 1

The speed of Car A = -55 km/h

Explanation:

Given, Time taken by Car A = 2.4 hour

and Time taken by Car B = 4 hour

Also, Car B traveled 22 mph faster than Car A

Let the speed of Car A = x km/h

Then the speed of Car B = (x + 22) km/h

As we know that Distance = Speed × Time

⇒ Distance of Car A = 2.4 × x = 2.4x km

and Distance of Car B = 4 × (x + 22) = 4(x + 22) km

Also it is given that distance traveled by both the car is same.

⇒ 2.4x = 4(x + 22)

⇒ 2.4x = 4x + 88

⇒ 2.4x - 4x = 88

⇒ -1.6x = 88

⇒ x = -55

Thus, the speed of Car A = -55 km/h

and, the speed of Car B = -55 + 22 = -33km/h

Answer 2

Car A traveled at 55 mph.

Explanation:

Suppose, the speed of Car A is
`x` mph.

As Car B traveled 22 mph faster than Car A , so the speed of Car B will be:
`(x+22) mph`

Given that, Car A traveled the distance in 2.4 hours and Car B traveled the distance in 4 hours.

As,
`Distance= Speed*Time`

So, the distance traveled by Car A
`=2.4x` miles

and the distance traveled by Car B
`=4(x+22)` miles

Given that, two cars traveled equal distances. So, the equation will be......

`2.4x=4(x+22)\\ \\ 2.4x=4x+88\\ \\ 2.4x-4x=52.8\\ \\ -1.6x=52.8\\ \\ x=(52.8)/(-1.6)=-33`

Thus, the speed of Car A will be -33 mph.