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A father leaves his money to his four children the first received 1/3 the second received 1/6 and the third received 2/5 how much did the remaining child receive

1 Answer

3 votes

Answer:

The remaining child got a fraction of
(1)/(10).

Explanation:

Lets take the fraction of the money fourth child got is
x

Addition of all these fractions should be equal to 1.


(1)/(3) +(1)/(6) +(2)/(5) +x=1


(10+5+12+30x)/(30) =1 (Taking a common denominator)


(27+30x)/(30) =1


27+30x=30


30x=3


x=0.1

Therefore,

The remaining child got a fraction of
(1)/(10).

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